How to export DataGridView to excel file

using System; using System.Windows.Forms; using System.Data; using System.Data.SqlClient; using Excel = Microsoft.Office.Interop.Excel; namespace WindowsApplication1 { public partial class Form1 : Form { public Form1() { InitializeComponent(); } private void button1_Click(object sender, EventArgs e) { SqlConnection cnn ; string connectionString = null; string sql = null; connectionString = "data source=servername;initial catalog=databasename;user id=username;password=password;"; cnn = new SqlConnection(connectionString); cnn.Open(); sql = "SELECT * FROM Product"; SqlDataAdapter dscmd = new SqlDataAdapter(sql, cnn); DataSet ds = new DataSet(); dscmd.Fill(ds); dataGridView1.DataSource = ds.Tables[0]; } private void button2_Click(object sender, EventArgs e) { Excel.Application xlApp ; Excel.Workbook xlWorkBook ; Excel.Worksheet xlWorkSheet ; object misValue = System.Reflection.Missing.Value; xlApp = new Excel.Application(); xlWorkBook = xlApp.Workbooks.Add(misValue); xlWorkSheet = (Excel.Worksheet)xlWorkBook.Worksheets.get_Item(1); int i = 0; int j = 0; for (i = 0; i <= dataGridView1.RowCount - 1; i++) { for (j = 0; j <= dataGridView1.ColumnCount - 1; j++) { DataGridViewCell cell = dataGridView1[j, i]; xlWorkSheet.Cells[i + 1, j + 1] = cell.Value; } } xlWorkBook.SaveAs("csharp.net-informations.xls", Excel.XlFileFormat.xlWorkbookNormal, misValue, misValue, misValue, misValue, Excel.XlSaveAsAccessMode.xlExclusive, misValue, misValue, misValue, misValue, misValue); xlWorkBook.Close(true, misValue, misValue); xlApp.Quit(); releaseObject(xlWorkSheet); releaseObject(xlWorkBook); releaseObject(xlApp); MessageBox.Show("Excel file created , you can find the file c:\\csharp.net-informations.xls"); } private void releaseObject(object obj) { try { System.Runtime.InteropServices.Marshal.ReleaseComObject(obj); obj = null; } catch (Exception ex) { obj = null; MessageBox.Show("Exception Occured while releasing object " + ex.ToString()); } finally { GC.Collect(); } } } }